In ABC AD is median and G is the point on AD such that AG GD 2 1 Then ar ABG ar ABC is equal to ........

Quantitative Aptitude (CGL) Geometry

In $\bigtriangleup$ ABC, AD is median and G is the point on AD such that AG : GD = 2: 1. Then ar( $\bigtriangleup$ ABG) : ar( $\bigtriangleup$ ABC) is equal to:

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SSC CGL 10 June 2019 Shift-3

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Explanation:

ABC is a triangle
AD is the median
Now AG:GD =2:1
So we can say G is the centroid.
Now Area of BDG = a
In ABD
Area of ABG :Area of BDG =AG:GD
So Area of ABG = 2a
we get Area of ABD =3a
Now Area of ABC = 2 Area (ABD) =6a
so ABG :ABC = 2/6 =1/3

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