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A father was twelve times as old as his son twenty years ago. Now he is twice as old as his son. What are the present ages
ofthe son and father?
22 and 44 years
27 and 54 years
33 and 66 years
15 and 30 years
- Let's denote the son's current age as x and the father's current age as 2x since the father is now twice as old as his son.
- Twenty years ago, the son's age was x−20 and the father's age was 2x−20.
- At that time, the father was twelve times as old as the son, so we have the equation: 2x−20=12(x−20).
- Solving the equation:
2x−20=12x−240
results in
220=10x,
so x=22.
- Therefore, the father is 2x=44.
- Let's go through the options:
- Option 1: 22 and 44 years.
- Option 2: 27 and 54 years.
- Option 3: 33 and 66 years.
- Option 4: 15 and 30 years.
- Based on calculations, the present ages are indeed 22 and 44 years.
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