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The ratio of the efficiencies of A, B and C, to do a certain workis 7 : 3 : 5. Working together, they can complete the work in 21
days. A and C worked together for 15 days. The remaining work will be completed by B alone in:
54 days
45 days
60 days
63 days
- A, B, and C's efficiency ratio is 7:3:5.
- The total work is completed by A, B, and C together in 21 days.
- Calculating the collective efficiency:
- Total efficiency = 7 + 3 + 5 = 15 units per day.
- Total work = total efficiency × total days = 15 units/day × 21 days = 315 units.
- A and C together have an efficiency of 7 + 5 = 12 units per day.
- They work together for 15 days, completing 12 units/day × 15 days = 180 units.
- Remaining work = 315 units - 180 units = 135 units.
- B's efficiency is 3 units/day.
- Days needed for B to complete the remaining work = 135 units / 3 units/day = 45 days.
- Correct Answer: Option 2: 45 days
By: santosh ProfileResourcesReport error
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