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3 men, 4 women and 6 boys together can complete a work in 6 days. A woman does triple the work a man does and a boy does
half the work a man does. How many women alone will be able to complete this work in 4 days?
7
8
6
9
- Let's assign a variable M to represent the work done by a man per day.
- Hence, a woman does 3M work per day, and a boy does M/2 work per day.
- In the given scenario, the daily work done by the group is:
- 3 men = 3M
- 4 women = 4 × 3M = 12M
- 6 boys = 6 × (M/2) = 3M
- Total = 3M + 12M + 3M = 18M
- Therefore, the work is completed in 6 days, so total work is 18M × 6 = 108M.
- If women alone need to complete this work in 4 days, they must do 108M work in 4 days.
- Hence, the required number of women is 108M ÷ (3M × 4) = 9 women.
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