A starts walking at 4 k mph and after 4 hours B starts cycling from the same point as that of A in t...........

Quantitative Aptitude (CGL) Time & distance

A starts walking at 4 k mph and after 4 hours, B starts cycling from the same point as that of A, in the same direction at 10 k

mph. After how much distance from the starting point will B catch up with A (Correct to two decimal places)?

This questions was previously asked in

SSC CGL 13 June 2019 Shift-3

View All ssc Previous Year Papers

25.67 km

26.67 km

24.67 km

23.67 km

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Explanation:

As per the given question,
Distance covered by man in 4 hour=4x4=16 km
Let cyclist and walking person will meet after time t and at the distance d from the starting point.
Hence, for cyclist t=10^d --------(i)
For the walking person, t= $_{4}^{d-16}$ ----------(ii)
From the equation (i) and (ii)