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When 2 is subtracted from each of the given n numbers, then the sum of the numbers so obtained is 102. When 5 is subtracted
from each of them, then the sum of the numbers so obtained is 12. What is the average of the given n numbers?
6.2
6.6
5.8
5.4
Let for 'n' numbers the average be 'x'. So, the total sum of 'n' numbers would be 'nx'. If 2 is subtracted from each 'n' numbers, then the resulted value to be subtracted becomes = 2n Thus, value of the total sum now = (nx - 2n) Given that, this value equals to 102. So, nx - 2n = 102 ...(1) Again when 5 is subtracted from each 'n' numbers, then the resulted value to be subtracted becomes = 5n × ×100 + 120 (300 − x) × 100 = 90 300 ? Thus, value of the total sum now = (nx - 5n) Given that, this value equals to 12. So, nx - 5n = 12 ...(2) Subtracting (2) from (1), we get: nx - 2n - (nx - 5n) = 102 - 12 ⇒ -2n + 5n = 90 ⇒ 3n = 90 ⇒ n = 90/3 = 30 There are 30 numbers. Putting n = 30, in eqn.(1), we get: (30)x - 2(30) = 102 ⇒ 30x - 60 = 102 ⇒ 30x = 162 ⇒ x = 162/30 = 5.4 The average of 30 numbers is 5.4.
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