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The least number which when divided by 4, 6, 8, 12 and 16 leaves a remainder of 2 in each case is.
46
50
48
56
- First, determine the least common multiple (LCM) of the numbers: 4, 6, 8, 12, and 16. The LCM is the smallest number divisible by all these numbers, which is 48.
- We want a number that leaves a remainder of 2, so we add 2 to the LCM. The number we seek is 48 + 2 = 50.
- So, the least number that when divided by 4, 6, 8, 12, and 16, leaves a remainder of 2 is 50.
- Option 1: 46 - Not correct, as it doesn't satisfy the condition with all divisors.
- Option 2: 50 - Correct. It satisfies the condition with all divisors.
- Option 3: 48 - Not correct. It leaves no remainder when divided.
- Option 4: 56 - Not correct, as it doesn't meet the remainder condition.
.
By: Parvesh Mehta ProfileResourcesReport error
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