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A circle is inscribed in a quadrilateral ABCD, touching sides AB, BC CD and DA at P, Q, R and S,respectively. If AS = 6cm, BC =
12 cm, and CR =5 cm,then the length ofAB (in cm) is:
13
11
15
12
Let’s break it down:
- In a tangential quadrilateral (where a circle touches all sides), the tangents from a single point to the circle are equal.
- So, from A, the segments to S and P have the same length: AS = AP = 6 cm.
- Similarly, from C, the segments to R and Q are the same: CR = CQ = 5 cm.
- The lengths of the sides are:
- AB: AP + PB
- BC: BQ + QC
- CD: CR + RD
- DA: DS + SA
- Let’s assign:
- AP = AS = 6
- BQ = BP (from B)
- CR = CQ = 5
- DS = DR (from D)
- The full side BC is BQ + QC = BQ + 5 = 12, so BQ = 7 cm.
- AB = AP + PB = 6 + PB. But PB = BQ = 7.
- So, AB = 6 + 7 = 13 cm
- Options:
- 13
- 11
- 15
- 12
- So, option 1 is correct. Your answer matches.
By: santosh ProfileResourcesReport error
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