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Pipes A and B can fill a tank in 12 hours and 16 hours respectively and pipe C can empty the full tank in 24 hours. All three pipes are opened together, but after 4 hours pipe B is closed. In how manyhours, the empty tank will be completely filled?
18
32
28
14
Correct Option is 1 - 18 hours
Time taken to fill a tank by Pipe B = 16 hours Time taken to empty a tank by Pipe C = 24 hours Formula used: Work = Efficiency x Time Calculation: LCM of 12, 16 and 24 is 48 Efficiency of A to fill the tank = (48/12) = 4 hours/day Efficiency of B to fill the tank (48/16) = 3 hours/day Efficiency of C to empty the tank = (48/24) = - 2 hours/day All three pipes opened together for 4 hours = [(4 + 3 − 2) x 4] ⇒ (5 × 4) = 20 unit Remaining unit = (48-20) = 28 unit Time taken by A and C together = [28/(4-2)] ⇒ (28/2) = 14 hours Now, Total time is taken to fill the empty tank = (14 + 4) hours ⇒ 18 hours The required time is 18 hours
By: santosh ProfileResourcesReport error
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