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If the 5-digit number 688xy is divisible by 3, 7 and 11, then what is the value of (5x + 3y)?
36
23
43
39
Correct option 4: 39
688xy is divisible by 3,7 and 11 Concept used: Divisibility rule of 3 - If sum of all digit of number is divisible by 3 then whole number is divisible by 3. Divisibility rule of 7 - To make a pair of 3 from unit digit than subtract left over pair, The result is divisible by 7. Divisibility rule of 11 - Sum of odd digit place - Sum of even digit place = 0 or multiple of 11. Calculation: 688xy is divisible by 3,7 and 11 For divisibility rule of 3, (x + y) = 2, 5, 8, 11 For divisibility rule of 11, (6+8+ y) - 18+ x) = 0 or 11 (14+ y)-(8+x) = 0 or 11 We take the value of y = 8 or x = 3 ⇒(14+8) - (83) = 0 or 11 ⇒(22-11) = 11 [divisible by 11] So, the value of x = 3 and y = 8 Now, (5x +-3y)=(5x3 + 3 x 8) ⇒ (15+24) ⇒39 :. The required value is 39
By: santosh ProfileResourcesReport error
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