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A and B together can complete a certain work in 20 days whereas B and C together can complete it in 24 days. If A is twice as
good a work man as C, then in what time will B alone do 40% of the same work?
12 days
15 days
18 days
10 days
- Given that A and B together can finish the work in 20 days:
- Combined work rate of A and B: 1/20 of the work per day.
- B and C together can finish it in 24 days:
- Combined work rate of B and C: 1/24 of the work per day.
- A is twice as efficient as C, implying:
- A = 2C in terms of working ability.
- To find B's work rate:
- Assume C's work rate as x. Then A's work rate is 2x.
- A + B = 1/20, hence 2x + B = 1/20.
- B + C = 1/24, hence B + x = 1/24.
- Solving these equations gives us B's work rate:
- Subtract the second from the first: (2x + B) - (B + x) = 1/20 - 1/24
- x = 1/120
- Substitute x = 1/120 into B + x = 1/24 to find B = 1/30.
- B's work rate is 1/30 of the work per day.
- To find time for B to do 40% of the work:
- 40% of work is 0.4 of the total work.
- Time = Work / Rate = 0.4 / (1/30) = 12 days.
Option:1 - 12 days is correct.
By: santosh ProfileResourcesReport error
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