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If 4 men and 6 boys can do a work in 8 days and 6 men and 4 boys can do the same work in 7 days, then how many days will 5
men and 4 boys take to do the same work?
5
8
6
7
Let’s break it down step by step:
- 4 men + 6 boys finish the work in 8 days. That means (4M + 6B) × 8 = 1 work unit.
- 6 men + 4 boys finish in 7 days. So (6M + 4B) × 7 = 1 work unit.
Let's turn these into equations for “work per day”:
- 4M + 6B = 1/8
- 6M + 4B = 1/7
Now multiply both out to clear fractions:
- 4M + 6B = 0.125
- 6M + 4B = 0.142857
Let’s solve:
- Multiply the first by 3: 12M + 18B = 3/8 = 0.375
- Multiply the second by 2: 12M + 8B = 2/7 = 0.28571
Subtract the second from the first:
- (12M + 18B) - (12M + 8B) = 0.375 - 0.28571
- 10B = 0.08929 ? B = 0.008929
Plug B back into the first equation:
- 4M + 6 × 0.008929 = 0.125
- 4M + 0.05357 = 0.125
- 4M = 0.07143 ? M = 0.017857
Now, what about 5 men and 4 boys?
- 5 × 0.017857 + 4 × 0.008929 = 0.089285 + 0.035714 = 0.125
That means 5 men and 4 boys do 0.125 (or 1/8) of the work per day. So, they will do the work in 8 days.
Here’s what that means for the options:
- Option 1, 5 days: Too fast.
- Option 2, 8 days: Spot on.
- Option 3, 6 days: Not matching the numbers.
- Option 4, 7 days: Still not matching.
By: santosh ProfileResourcesReport error
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