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Three alarm clocks ring their alarms at regular intervals of 20, 21 and T minutes respectively. If the clocks beep together at 12 noon, for which value of T would they beep together
again at the earliest ?
8 minutes
18 minutes
28 minutes
38 minutes
- The three alarm clocks ring at regular intervals: every 20, 21, and T minutes.
- They all beep together at 12 noon. To find when they'll next beep together, find the least common multiple (LCM) of the intervals.
- The LCM of 20 and 21 is 420 minutes.
- To find when all three clocks beep together, calculate the LCM of 420 and T.
- We need the smallest value of T from the options, where LCM(420, T) is the smallest.
Option 1: T = 8 minutes
- LCM(420, 8) = 840
Option 2: T = 18 minutes
- LCM(420, 18) = 1260
Option 3: T = 28 minutes
- LCM(420, 28) = 420 (since 28 divides 420)
Option 4: T = 38 minutes
- LCM(420, 38) = 7980
- Answer: Option 3 - 28 minutes is correct.
By: Parvesh Mehta ProfileResourcesReport error
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