A train is traveling at 48 kmph It crosses another train having half of its length traveling in oppo...........

Quantitative Aptitude ( CCS) Problems on trains

A train is traveling at 48 kmph . It crosses another train having half of its length , traveling in opposite direction at 42 kmph, in 12 seconds. It also passes a railway platform in 45 seconds. What is the length of the platform ?

500

400

360

480

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Explanation:

Speed of train 1 = 48 kmph
Let the length of train 1 = 2x meter
Speed of train 2 = 42 kmph
Length of train 2 = x meter (because it is half of train 1's length)
Distance = 2x + x = 3x
Relative speed= 48+42 = 90 kmph = (90*5/18) m/s = 25 m/s
Time = 12 s
Distance/time = speed

=3x/12 = 25 $\Rightarrow$ (25*12)/3

Length of the first train = 2x = 200 meter
Time taken to cross the platform= 45 s
Speed of train 1 = 48 kmph = 480/36 = 40/3 m/s
Distance = 200 + y [where y is the length of the platform]

x =100m => 200+y = 45* 40/3
$\Rightarrow$ y = 400m

Hence, option 2 is the correct answer.

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