If xxx is a real number then the minimum value of x2 minus 8x 17 is ........

Mathematics (CUET) Previous Year Papers

If xxx is a real number, then the minimum value of x²−8x+17 is:

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CUET Mathematics Previous Year Question Paper 2022

-1

- To find the minimum value of x² - 8x + 17, we can complete the square:

x² - 8x + 17 = (x - 4)² + 1

- The minimum value of (x - 4)² happens when x = 4, so (x - 4)² = 0.

- Substitute back: (0) + 1 = 1.

- So, the minimum value of the expression is 1.

- Now, check the options:

1. Option:1, -1 ? Not correct (smaller than possible)

2. Option:2, 0 ? Not correct (also lower than the true minimum)

3. Option:3, 1 ? Correct answer

4. Option:4, 2 ? Not correct (higher than the true minimum)

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