Explanation:

For a spherical shell, Gauss's theorem helps in understanding the electric field behavior.

Inside the shell, the electric field is zero because there is no enclosed charge.

Outside, the shell behaves like a point charge, with the electric field \( E = \frac{Q}{4\pi\varepsilon_0r^2} \), showing inverse square behavior.

Option 2 fails as it describes an incorrect relationship for outside the shell.

Option 3 misunderstands the symmetry application.

Option 4 mischaracterizes the constant nature of the outside field.