S1 can do a piece of work alone in 9 days S2 can do the same work alone in 18 days while S...........

Quantitative Aptitude (MTS) Time and work

S₁can do a piece of work alone in 9 days, S₂can do the same work alone in 18 days, while S₃can do it alone in 27 days. They

work together and complete the work, and receive a total of Rs726 as payment for doing the work. What is the combined share

of s2 and s3, taken together from the above amount?

This questions was previously asked in

SSC MTS 5th July 2022 Shift-3

Rs270

Rs300

Rs330

Rs360

- To find how much each worker can do in one day, calculate their work rate:

- S₁ can do 1/9 of the work in one day.

- S₂ can do 1/18 of the work in one day.

- S₃ can do 1/27 of the work in one day.

- Combine their work rates to find the total work per day:

- Total = \( \frac{1}{9} + \frac{1}{18} + \frac{1}{27} \).

- Simplify the fractions:

- Total = \( \frac{6}{54} + \frac{3}{54} + \frac{2}{54} = \frac{11}{54} \).

- Calculate the share of payment based on individual contributions:

- S₂'s contribution = \( \frac{3}{54} \).

- S₃'s contribution = \( \frac{2}{54} \).

- Combined share of S₂ and S₃:

- \( \frac{3 + 2}{11} \times 726 = \frac{5}{11} \times 726 = 330 \).

- Highlight correct answer:

- Option 3: Rs330

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