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The lengths of one side and a diagonal of a rectangle are 63 cm and 65 cm, respectively. What is the perimeter (in cm) of a
square whose area is one-seventh of that of the rectangle?
36
64
24
48
- In a rectangle, the diagonal forms a right triangle with the sides. Given sides are 63 cm and diagonal is 65 cm.
- Use the Pythagorean theorem to find the missing side: \( x^2 + 63^2 = 65^2 \).
- Solving gives \( x = 16 \).
- The area of the rectangle: \( 63 \times 16 = 1008 \) square cm.
- One-seventh of the area: \( 1008 / 7 = 144 \) square cm.
- The area of the square is 144 square cm. Thus, the side length of the square is \(\sqrt{144} = 12 \) cm.
- The perimeter of the square: \( 4 \times 12 = 48 \) cm.
- Correct answer is: Option: 4 - 48
By: santosh ProfileResourcesReport error
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