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Five players, ‘a’, ‘b’, ‘c’, ‘d’ and ‘e’, scored some runs during a match.
1. ‘b’ scored a half century, but did not score a century.
2. ‘d’ scored more runs than ‘c’, but less runs than ‘b’.
3. ‘a’ scored 37 runs, which is less than ‘c’.
4. ‘e’ scored 29 runs more than ‘d’.
5. ‘c’ scored 21 runs less than ‘b’.
What is likely to be the score of ‘e’?
134
62
70
58
Let's analyze the statements to find the score of 'e':
- Statement 1: 'b' scored a half-century but not a century. So, 50 = b < 100.
- Statement 2: 'd' scored more than 'c' but less than 'b'. Therefore, c < d < b.
- Statement 3: 'a' scored 37 runs, which is less than 'c'. So, c > 37.
- Statement 4: 'e' scored 29 runs more than 'd'. Therefore, e = d + 29.
- Statement 5: 'c' scored 21 runs less than 'b'. Hence, c = b - 21.
Let's deduce the scores:
- From Statement 5, since c = b - 21 and c > 37, b should be at least 59 (since 59 - 21 = 38, which is greater than 37).
- But, b can't be 100 or more, and must be satisfied with 59 = b < 100.
- Since c = b - 21, c will be between 38 and 79 (using b between 59 and 100).
- From Statement 2 and 3, with c > 37, we have c could range up to 79, so if c is 38, then d must be between 39 and 79.
- Finally, from Statement 4, where e = d + 29, e could be from 68 to 108.
By arranging ranges with our options:
- If d is 41, then e = 70, which matches Option 3.
Considering all above deductions, the score of 'e' is likely:
- Option 3: 70
.
By: santosh ProfileResourcesReport error
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