The speed of a motor boat in still water and the speed of the current of water are in the ratio 20 4...........

Quantitative Aptitude (MTS) Boats and Streams

The speed of a motor-boat in still water and the speed of the current of water are in the ratio 20 : 4. To go a certain distance

along the current the boat takes 4 hours. Find the time taken by the boat to cover the same distance against the current.

This questions was previously asked in

SSC MTS 25th July 2022 Shift-1

6 hours

8 hours

12 hours

10 hours

- The speed ratio of the motor-boat in still water to the current is 20:4. This simplifies to 5:1.

- Let the speed of the boat in still water be 20x and the speed of the current be 4x.

- When going downstream, the effective speed is \(20x + 4x = 24x\).

- When going upstream, the effective speed is \(20x - 4x = 16x\).

- The boat takes 4 hours to travel the distance downstream.

- Distance covered downstream = Speed \(\times\) Time = \(24x \times 4 = 96x\).

- To cover the same distance upstream \((96x)\), with a speed of \(16x\), the time is \(\frac{96x}{16x} = 6\) hours.

- The correct answer is Option 1: 6 hours.

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