send mail to support@abhimanu.com mentioning your email id and mobileno registered with us! if details not recieved
Resend Opt after 60 Sec.
By Loging in you agree to Terms of Services and Privacy Policy
Claim your free MCQ
Please specify
Sorry for the inconvenience but we’re performing some maintenance at the moment. Website can be slow during this phase..
Please verify your mobile number
Login not allowed, Please logout from existing browser
Please update your name
Subscribe to Notifications
Stay updated with the latest Current affairs and other important updates regarding video Lectures, Test Schedules, live sessions etc..
Your Free user account at abhipedia has been created.
Remember, success is a journey, not a destination. Stay motivated and keep moving forward!
Refer & Earn
Enquire Now
My Abhipedia Earning
Kindly Login to view your earning
Support
Type your modal answer and submitt for approval
The radius of a cylinder is increased by 60% and radius of base is decreased by 20%. What is percentage increase in it’s volume?
105.6%
105.2%
104.8%
105.8%
- The volume of a cylinder is given by the formula \(V = \pi r^2 h\), where \(r\) is the radius and \(h\) is the height.
- Initially, let's assume the original radius is \(r\) and the height is \(h\).
- With a 60% increase in the radius, the new radius \(r_1\) becomes \(1.6r\).
- With a 20% decrease in the height, the new height \(h_1\) becomes \(0.8h\).
- The new volume \(V_1\) is calculated as \(V_1 = \pi (1.6r)^2 (0.8h)\).
- Simplifying gives: \(V_1 = \pi \cdot 2.56r^2 \cdot 0.8h = \pi \cdot 2.048r^2 h\).
- The percentage increase in volume is \(((2.048 - 1) / 1) \times 100\%\).
- This equals \(104.8\%\).
- Correct Answer: Option 3, 104.8%
By: santosh ProfileResourcesReport error
Access to prime resources
New Courses