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Riya walked 90 m towards the north from her house, and then took a right turn and walked 60 m to reach the market. Then, she took
a left turn and walked a few meters from the market to reach the post office, from where she took a left turn again and walked 160 m
to reach the school. If the air distance between Riya’s house and the school is 260 m, what is the air distance between the market and
the post office?
180 m
120 m
150 m
100 m
- Riya walks 90 m north from her house and then 60 m east to the market.
- She then walks an unknown distance to the post office after turning left (north).
- Turning left again (west), she walks 160 m to reach the school.
- The air distance between the house and school is 260 m.
Using these steps:
- Both the house and school are in a straight line from the market without deviation, hence:
- The total north-south distance: \(90 + x + 160 = 260\), where \(x\) is the distance from market to the post office.
- Solving gives the house-school linear alignment (using Pythagoras or observing alignment).
Let's deduce:
- The east-west distance from home to school should equal 60 m (market east tweak included).
- Through the rationale and alignment checks, one of these indirectly supports that \(x = 150 \, \text{m}\).
Option 3: 150 m is correct as per alignment solutions and logical deductions.
YOUR ANSWER IS WRONG
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