In an election between two candidates a candidate who gets 72 of votes is elected by a majority of 5...........

Quantitative Aptitude (CHSL) Percentage

In an election between two candidates, a candidate who gets 72% of votes is elected by a majority of 572 votes. Find the total

number of the votes polled. (assuming all votes are valid)

This questions was previously asked in

SSC CHSL 3rd June 2022 Shift-2

1300

900

1500

1100

- To find the total number of votes, let the total be represented as \( x \).

- The winning candidate received 72% of the votes, so the other candidate received 28%.

- The difference in votes between the two candidates is given as 572.

- Therefore, 72% of the votes minus 28% of the votes equals 572.

- This translates to 44% of the total votes being equal to 572.

- We write the equation: \( 0.44x = 572 \).

- Solve for \( x \) by dividing both sides by 0.44: \( x = \frac{572}{0.44} \).

- This gives \( x = 1300 \).

- Option 1: 1300 This is the correct total number of votes.

- Option 2: 900 – This does not satisfy the equation.

- Option 3: 1500 – This also does not satisfy the equation.

- Option 4: 1100 – This is incorrect as per calculations.

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