Anjali and Babita are running on a circular track in opposite directions from same time at same poin...........

Quantitative Aptitude (CHSL) Time & distance

Anjali and Babita are running on a circular track in opposite directions from same time at same point with speeds of 8 m/sec and 6 m/sec, respectively. If the length of the circular track is 960 m, how many times distinct points they will meet?

This questions was previously asked in

SSC CHSL 9th June 2022 Shift-3

View All SSCCHSL Previous Year Papers

7 times

6 times

12 times

14 times

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Explanation:

Correct option 1: 7 times

Solution

Speed of Anjali = 8 m/sec
Speed of Babita = 6 m/sec
Formula used:
Speed = Distance/Time
Solution:
From the given data,
Anjali can complete a round in = 960/8 = 120 seconds
Babita can complete a round in = 960/6 = 160 seconds
They meet again at the starting point in = LCM(120,160) = 480 seconds Now, relative speed of Anjali and Babita = 8 +6 = 14 m/s
When they meet on the track, they both covered 960 m together.
Time taken by them to cover 960 m = (960/14) seconds
After every (960/14) seconds, they will meet on the track.
So in 480 seconds, they meet
480/(960/14) = 7 times