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Directions: In a football tournament. There are four football teams Chennai, Mumbai, Delhi, and Kolkata each will play against each other Two times.
1. One match will be in-home and another match will be away.
2. Each team will get 2 game points when they hit a goal and they will lose 1 game point when they concede a goal.
3. A team will get 5 points in winning a game. To qualify for finals a team should get above 10 points.
Note:
(i) Team Chennai won 3 matches Mumbai won 5 matches and Delhi and Kolkata have won the remaining matches equally.
(ii) Two match between Kolkata and Delhi is drawn due to the equal number of goals.
The average of Table points of Mumbai and Chennai is how much percentage of Chennai table points?
100/3%
200/3%
50/3%
400/3%
250/3%
Let’s break it down:
- Four teams: Chennai, Mumbai, Delhi, Kolkata. Each team plays every other team twice (one home, one away). That’s 3 opponents × 2 = 6 matches per team, 12 total matches.
- Scoring:
- +2 game points for each goal scored
- –1 game point for each goal conceded
- +5 table points for winning a match
- To qualify for finals, a team needs more than 10 table points
- Wins: Chennai = 3 wins, Mumbai = 5 wins, Delhi and Kolkata split the other (12 – 3 – 5 = 4) matches evenly: Delhi = 2 wins, Kolkata = 2 wins.
- Delhi vs. Kolkata: Their two matches were both draws.
Now, for the main question:
- Average table points of Mumbai and Chennai as a percentage of Chennai's points? (Match points, not game points, are relevant here.)
Let’s calculate:
- Mumbai: 5 wins × 5 = 25 table points
- Chennai: 3 wins × 5 = 15 table points
Average = (25 + 15) / 2 = 20
Percentage = (20 / 15) × 100 = 133.33...%, or 400/3%
Here’s the bottom line:
- Option 4 (400/3%) is exactly right.
This checks out with the calculations and how the points system is explained. Nice work.
By: Parvesh Mehta ProfileResourcesReport error
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