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Directions: Study the information given below carefully and answer the questions given below. Ten people sitting in two parallel rows. Row 1 consist of A, B, C, D, E, all the person sitting in row 1 are facing south. Row 2 consist of F, G, H, I, J, all of them are facing north.
All ten people have a different number of chocolates with them. The number of chocolates they have are 6, 1, 11, 12, 9, 10, 8, 4, 2 and 7.
Neither D nor C is sitting at the extreme ends. F has an odd number of chocolates. E is sitting opposite to J who is sitting second to one of the extreme ends. J has the highest number of chocolates. H is sitting second to the left of J and is facing the one who has 6 chocolates. The one who is sitting third to the left end of the first row has a prime number of chocolates. E has more number of chocolates than I. B who is sitting at the left end has 11 number of chocolates, 9 more than the one who is sitting at the right end of the same row. A is sitting diagonally opposite to I who has even number of chocolates. D is sitting at the right side of C. The number of people sitting to the right side of G is equal to the number of people sitting at the left side of G. Addition of the number of chocolates owned by F and H makes a perfect square and that addition is less than the number of chocolates owned by G.
What is the position of F with respect to J?
Third to the left
Third to the right
second to the left
Second to the right
None of these
- We have ten people in two rows, with people in Row 1 facing south and those in Row 2 facing north.
- B is at the left extreme of Row 1 with 11 chocolates; E is opposite J.
- J is second from one extreme and has the highest number of chocolates (12).
- H, second to J's left, faces the person with 6 chocolates, who must be A.
- D and C are not at the ends, and D is right of C.
- A and F are diagonally aligned with I. I has an even chocolate number and fewer than E.
- F has an odd number of chocolates; F and H's total chocolates form a perfect square.
- G is centered.
- The prime number of chocolates is at Row 1's third left position, which should be E with 7 chocolates, as 7 is prime.
Given these points, F will be third to the left of J (both on Row 2).
Answer: Third to the left
By: Parvesh Mehta ProfileResourcesReport error
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