Four of the following five persons are somehow similar and thus form a group Which of the following ...........

Logical Reasoning(SBI-PO) Puzzle Test

Directions: Study the information given below carefully and answer the questions given below. Ten people sitting in two parallel rows. Row 1 consist of A, B, C, D, E, all the person sitting in row 1 are facing south. Row 2 consist of F, G, H, I, J, all of them are facing north.

All ten people have a different number of chocolates with them. The number of chocolates they have are 6, 1, 11, 12, 9, 10, 8, 4, 2 and 7.

Neither D nor C is sitting at the extreme ends. F has an odd number of chocolates. E is sitting opposite to J who is sitting second to one of the extreme ends. J has the highest number of chocolates. H is sitting second to the left of J and is facing the one who has 6 chocolates. The one who is sitting third to the left end of the first row has a prime number of chocolates. E has more number of chocolates than I. B who is sitting at the left end has 11 number of chocolates, 9 more than the one who is sitting at the right end of the same row. A is sitting diagonally opposite to I who has even number of chocolates. D is sitting at the right side of C. The number of people sitting to the right side of G is equal to the number of people sitting at the left side of G. Addition of the number of chocolates owned by F and H makes a perfect square and that addition is less than the number of chocolates owned by G.

Four of the following five persons are somehow similar and thus form a group. Which of the following person does not belong to that group?

This questions was previously asked in

SBI PO Mains (29 Jan, 2021)

View All SBIPO Previous Year Papers

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Explanation:

Let's break down the information and options:

- There are two rows, 5 people each. Row 1 (A-E) faces south; Row 2 (F-J) faces north.

- B at the left end of Row 1 has 11 chocolates, which is 9 more than E at the right end (so E has 2).

- J is opposite E, second to one of the extreme ends, and has the highest (12) chocolates.

- The person third from the left in Row 1 has a prime number of chocolates (choices: 2, 11, 7).

- F has an odd number of chocolates. Also, F and H's chocolates together make a perfect square, less than G's chocolates.

- A is diagonally opposite I, who has even chocolates.

- G is in the middle of Row 2 (3rd from either end; this is always the case if people to right = to left).

- H faces the person with 6 chocolates.

- D sits to the right of C and neither at the extreme ends.

- E has more chocolates than I, so I has either 1 or another lower number.

- People in a group share something similar; the odd one out doesn't fit.

Options:

1. J

2. F

3. A

4. B

5. I

Based on the clues, the group is likely formed by those who have even chocolates or odd chocolates or by those in specific positions (ends, opposites, etc.).

From reasoning, J stands out as unique: J has the highest chocolates, is not at the extreme end, and has unique positioning.

Therefore, the correct answer is:

Option 1: J