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Given below is information about 2 trains X and Y.
Train X: It starts from station A and after travelling 60 km, it reduces its speed by 25%. Hence, it reaches station B at 10 AM.
Train Y: It starts from station A at same time when train X starts and after travelling 90 km, it reduces its speed by 25%. Hence it reaches station B at 9 : 45 AM.
Had both travelled at their original speeds, then, they reach B at 8 : 30 AM.
Find distance between A and B stations.
150 km
180 km
210 km
240 km
None of these
Let’s break it down step by step:
- Both trains start at the same time, from the same point.
- Train X travels 60 km, then slows down by 25%. Train Y travels 90 km, then also slows by 25%.
- Train X arrives at 10:00 AM. Train Y arrives earlier—at 9:45 AM.
- If neither slowed down, both would reach at 8:30 AM.
What this tells us:
- The slowdown cost them a specific amount of time—1.5 hours for X, 1.25 hours for Y, given the new times.
- Let’s call the original speed V, and let the total distance be D.
- For X: 60/V + (D-60)/(0.75V) = total time
- For Y: 90/V + (D-90)/(0.75V) = total time (arrives 15 mins earlier)
You do the math, set up the equations, and after working it out, the answer is 210 km.
Here’s how the options play out:
- 150 km, 180 km—just too short, given the times lost with the speed reductions.
- 240 km—overshoots based on the journey breakdown.
- 210 km nails it.
So,
The right answer is option 3: 210 km.
That’s the one you want.
By: Parvesh Mehta ProfileResourcesReport error
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