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Directions: Answer the questions based on the information given below.
A right circular cylindrical vessel is filled with a mixture of milk and water. The quantity of milk to that of water in the mixture is in the ratio of 5 : 3 respectively. x ml of the total given mixture is sold and replaced with x ml of pure milk. The ratio between the resultant quantity of milk to that of water in the resultant mixture is in the ratio of 75 : 13 respectively. The quantity of mixture which is sold earlier was 104 ml less that the original quantity of the given mixture in the vessel.
If 0.25x ml of the initial mixture is sold and 0.75x ml pure milk and 0.05x ml water is added to the vessel then find the final total quantity of the resultant mixture in the given vessel?
332 ml
342 ml
352 ml
362 ml
372 ml
- We start with a cylindrical vessel with a milk-water mixture in the ratio 5:3.
- \( x \) ml of this mixture is sold, reducing the total amount in the vessel.
- We’re informed that the sold amount equals the initial amount minus 104 ml.
- After selling and replacing with \( x \) ml of milk, the new milk-to-water ratio is \( 75:13 \).
- An intermediate step: 0.25x ml of mixture is sold, then 0.75x ml milk and 0.05x ml water are added.
- Calculating based on these details, the final total quantity is examined for each option.
- The final calculations confirm the amount to be 352 ml.
By: Parvesh Mehta ProfileResourcesReport error
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