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Two students appeared for an examination. One of them secured 22 marks more than the other and his marks were 55% of the sum of their marks. The marks obtained by them are _______.
121 and 99
43 and 21
58 and 36
86 and 64
Let’s break down the problem:
- Let the marks of the two students be x and y, with x > y.
- Given: x = y + 22
- Also, x = 55% of (x + y) ? x = 0.55(x + y)
Let’s solve:
- From x = 0.55(x + y):
x = 0.55x + 0.55y
x - 0.55x = 0.55y
0.45x = 0.55y
x/y = 0.55/0.45 = 11/9
So, x = (11/9)y
- From x = y + 22:
(11/9)y = y + 22
(11y - 9y)/9 = 22
2y/9 = 22
2y = 198
y = 99
x = 99 + 22 = 121
Now, let’s check the options:
- Option 1: 121 and 99
- Diff = 22, and 121/(121+99) = 121/220 = 0.55 Both statements satisfied.
- Option 2: 43 and 21
- Diff = 22, but 43/(43+21) ˜ 0.67 Not matching second condition.
- Option 3: 58 and 36
- Diff = 22, but 58/(58+36) ˜ 0.62 Not matching.
- Option 4: 86 and 64
- Diff = 22, but 86/(86+64) ˜ 0.57 Not matching.
Correct answer:
- 121 and 99 (Option 1)
- Satisfies both conditions.
By: sunny bhonsle ProfileResourcesReport error
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