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What approximate value will come in the place of the question mark ‘?’ in the following question?
130.11% of 110.04 – 220.24% of 129.88 + 24.88% of ? = 44.07% of 224.98 + 145.1% of 20.02
1074
1078
1080
1005
1085
Let's break down the expression step by step:
- 130.11% of 110.04:
\( \frac{130.11}{100} \times 110.04 \approx 143.414 \)
- 220.24% of 129.88:
\( \frac{220.24}{100} \times 129.88 \approx 286.073 \)
- 44.07% of 224.98:
\( \frac{44.07}{100} \times 224.98 \approx 99.148 \)
- 145.1% of 20.02:
\( \frac{145.1}{100} \times 20.02 \approx 29.056 \)
- Expression:
\( 143.414 - 286.073 + 0.2488x = 99.148 + 29.056 \)
- Solving for '?':
\( 143.414 - 286.073 + 0.2488x = 128.204 \)
\( -142.659 + 0.2488x = 128.204 \)
\( 0.2488x = 128.204 + 142.659 \)
\( 0.2488x = 270.863 \)
\( x \approx \frac{270.863}{0.2488} \approx 1088.11 \)
- The closest option to 1088.11 is Option 5: 1085
By: Parvesh Mehta ProfileResourcesReport error
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