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Two equations I and II are given below in the question. You have to solve these equations and give the answer.
I. 9x2 – 15x + 4 = 0
II. 7y2 + 18y + 8 = 0
x < y
x > y
x ≤ y
x ≥ y
x = y or the relation between x and y can't be established.
To solve the equations and compare the values of x and y, here's what you need to do:
- Equation I: 9x² – 15x + 4 = 0
- This is a quadratic equation of the form ax² + bx + c = 0.
- To find x, use the quadratic formula: x = [-b ± v(b²-4ac)] / 2a.
- Substituting a = 9, b = -15, c = 4, we get the roots x1 = 1 and x2 = 4/9.
- Equation II: 7y² + 18y + 8 = 0
- Similarly, apply the quadratic formula: y = [-b ± v(b²-4ac)] / 2a.
- Substituting a = 7, b = 18, c = 8, we get the roots y1 = -2 and y2 = -4/7.
- Comparison:
- x1 (1) is greater than both y1 (-2) and y2 (-4/7).
- x2 (4/9) is greater than both y1 (-2) and y2 (-4/7).
- Conclusion: x > y in all cases.
- Correct Answer:
- Option 2: x > y
By: Parvesh Mehta ProfileResourcesReport error
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