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Kamal decided to invest his amount in a ratio of 3 : 2 in two schemes A and B at a rate of simple interest of 4% and 8 for 4 years and 2 years respectively. If he gets Rs. 12,00 as SI from both the scheme together, find the amount he invested.
Rs. 6000
Rs. 6500
Rs. 7500
Rs. 8500
Rs. 7000
To solve this problem, let's break it down step by step:
- Kamal invests in two schemes, A and B, in a ratio of 3:2.
- Simple interest for Scheme A is at 4% for 4 years.
- Simple interest for Scheme B is at 8% for 2 years.
- Total simple interest from both schemes is Rs. 1200.
Let’s denote the amounts invested in Schemes A and B as 3x and 2x respectively.
1. Calculate Simple Interest (SI) for each scheme:
- Scheme A:
- SI = (3x * 4% * 4) = 0.48x.
- Scheme B:
- SI = (2x * 8% * 2) = 0.32x.
2. Total SI = SI from Scheme A + SI from Scheme B = Rs. 1200:
- 0.48x + 0.32x = 1200
- 0.80x = 1200
- x = 1500
3. Find the total investment (3x + 2x):
- Amount invested = 3x + 2x = 5x
- Total amount = 5 * 1500 = Rs. 7500.
- Correct Answer: Option 3: Rs. 7500
By: Parvesh Mehta ProfileResourcesReport error
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