A train moving with the speed of 25 m s crosses a platform which is one third of its length in 20 se...........

Quantitative Aptitude(IBPS CL) Time & distance

A train moving with the speed of 25 m/s crosses a platform which is one third of its length in 20 seconds. What would be the length of the train?

This questions was previously asked in

IBPS Clerk Prelims

325 m

125 m

275 m

225 m

375 m

Let's break it down:

- Given speed: 25 m/s.

- Time taken to cross the platform: 20 seconds.

- Distance covered in crossing: Speed × Time = 25 m/s × 20 s = 500 meters.

- The total distance includes the length of the train and the platform.

- Platform length: One third of the train's length.

- Therefore, if the train's length is \( L \), the platform is \( \frac{L}{3} \).

- The equation becomes: \( L + \frac{L}{3} = 500 \).

- Solve for \( L \): \( \frac{4L}{3} = 500 \) ? \( 4L = 1500 \) ? \( L = 375 \).

- Correct answer: Option 5, 375 m

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