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6 years ago, the ratio of age of A and B is 7 : 6. A is 6 years older than C. If the sum of the present age of B and C is 32, then find the present age of C.
21 years
14 years
18 years
28 years
12 years
To solve this, we need to figure out the present ages based on given information.
- 6 years ago, the ratio of A's age to B's age was 7:6. So, let their ages be 7x and 6x then.
- Now, A is 6 years older than C. This translates to: A = C + 6.
- The present sum of B and C's ages is 32: B + C = 32.
With this, let's express A's and B's ages now:
- 6 years ago:
- A = 7x, B = 6x
- Now:
- A = 7x + 6, B = 6x + 6
Given:
- B + C = 32
- A = C + 6
From the age ratio condition:
- A - 6 = 7x
- B - 6 = 6x
From the above equations:
- B = 6x + 6
- C = 32 - B = 32 - (6x + 6) = 26 - 6x
Using A = C + 6:
- \(A = C + 6 = (26 - 6x) + 6 = 32 - 6x\)
- \(7x + 6 = 32 - 6x\)
Solving this:
- \(7x + 6x = 32 - 6\)
- \(13x = 26\)
- \(x = 2\)
Calculate C's present age:
- C = 26 - 6(2) = 26 - 12 = 14
- Correct Answer: Option 2 - 14 years
-
By: Parvesh Mehta ProfileResourcesReport error
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