send mail to support@abhimanu.com mentioning your email id and mobileno registered with us! if details not recieved
Resend Opt after 60 Sec.
By Loging in you agree to Terms of Services and Privacy Policy
Claim your free MCQ
Please specify
Sorry for the inconvenience but we’re performing some maintenance at the moment. Website can be slow during this phase..
Please verify your mobile number
Login not allowed, Please logout from existing browser
Please update your name
Subscribe to Notifications
Stay updated with the latest Current affairs and other important updates regarding video Lectures, Test Schedules, live sessions etc..
Your Free user account at abhipedia has been created.
Remember, success is a journey, not a destination. Stay motivated and keep moving forward!
Refer & Earn
Enquire Now
My Abhipedia Earning
Kindly Login to view your earning
Support
Type your modal answer and submitt for approval
A train starting from rest with a uniform acceleration attains a speed of 108 km/h in 5 minutes. The distance covered by the train in attaining the speed is
9000 m
4500 m
355m
108 m
Let’s solve the problem step-by-step:
- Initial speed (u) = 0 (train starts from rest)
- Final speed (v) = 108 km/h = 30 m/s (since 108 × 1000 / 3600 = 30)
- Time (t) = 5 min = 300 seconds
- Using the formula: v = u + at
30 = 0 + a × 300
? a = 30 / 300 = 0.1 m/s²
- Distance covered (s) = ut + (1/2)at²
s = 0 + 0.5 × 0.1 × (300)²
s = 0.05 × 90000 = 4500 m
- Option 1: 9000 m – Too high (would mean almost double the acceleration)
- Option 2: 4500 m – Correct answer
- Option 3: 355 m – Too low (not possible in 5 minutes)
- Option 4: 108 m – Much too low (would be done in a few seconds at this speed)
By: santosh ProfileResourcesReport error
Access to prime resources
New Courses