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2 and 3 but not 37
3 and 37 but not 2
2 and 37 but not 3
2, 3 and 37
Let's analyze 222333 + 333222 for divisibility:
- Divisibility by 2: Any odd number raised to any power is odd, and any even number raised to a positive power is even. Here, 222333 is even, 333222 is odd. So, even + odd = odd. Thus, it's not divisible by 2.
- Divisibility by 3:
- 222 = 0 mod 3, so 222333 = 0 mod 3.
- 333 = 0 mod 3, so 333222 = 0 mod 3.
- So their sum is divisible by 3.
- Divisibility by 37:
- Note: 222 = -1 mod 37, 333 = 1 mod 37.
- 222333 = (-1)333 = -1 mod 37.
- 333222 = 1222 = 1 mod 37.
- So sum = -1 + 1 = 0 mod 37. Thus, divisible by 37.
Options:
1. 2 and 3 but not 37 –
2. 3 and 37 but not 2 –
3. 2 and 37 but not 3 –
4. 2, 3 and 37 –
Correct Answer:
Option: 2, 3 and 37 but not 2
By: Parvesh Mehta ProfileResourcesReport error
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