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A and B together can do a piece of work in 12 days which B and C together can do in 16 days. After A has been working at it for 5 days and B for 7 days, C finishes it in 13 days. In how many days could each do the work by himself ?
24, 12, 36
24, 16, 12
16, 48, 24
24, 36, 12
Solution: Total work = 48 ,… A+B = 4 ….B+C = 3 now, 5A + 7B + 13C = 48 split it 5A +5B + 2B + 2C + 11C = 48 so 5*4 + 2*3 + 11c = 48 so 11c = 22 …… c = 2 so c alone = 48/2 = 24 A — 48/3 = 16 B— 48/1 =48
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