The least number which when divided by 12 15 20 or 54 leaves a remainder of 4 in each case is ........

Quantitative Aptitude (CUET) LCM, HCF

The least number, which when divided by 12, 15, 20 or 54 leaves a remainder of 4 in each case is:

456

454

544

540

LCM of (12, 15, 20, 54)

⇒ 4 × 3 × 5 × 9 = 540

∴ The required number is

540 + 4 = 544

⇒ Because when divided by LCM each is divided completely.

By adding 4 in LCM, it leaves remainder 4.

Hence, option 3 is the correct answer.

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