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If the sum of two numbers is 55 and the H.C.F. and L.C.M. of these numbers are 5 and 120 respectively, then the sum of the reciprocals of the numbers is equal to:
55/601
601/55
11/120
120/11
Let the numbers be a and b.
Then, a + b = 55 and ab = 5 x 120 = 600.
The required sum = 1/a + 1/b
= a + b /ab = 55/600 = 11/120
Hence, option 3 is the correct answer.
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