500 kg of ore contained a certain amount of iron After the first blast furnace process 200 kg of sla...........

Numerical Ability Percentage

500 kg of ore contained a certain amount of iron. After the first blast furnace process, 200 kg of slag containing 12.5% of iron was removed. The percentage of iron in the remaining ore was found to be 20% more than the percentage in the original ore. How many kg of iron were there in the original 500 kg ore?

90.5

89.2

87.3

81.2

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Explanation:

Initially ‘x’ kg of iron in 500 kg ore.
Iron in the 200 kg of removed =200*12.5/100= 25 kg.
The percentage of iron in the remaining ore was found to be 20% more than the percentage in the original ore So (x-25)/300 = (120/100)*x/500
=> x – 25 = 18x/25
=> 7x = 625
=> x = 89.2