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Multiple Choice Questions

If 5 engines consume 6 metric tonnes of coal when each is running 9 hours a day How much coal in met...........

Numerical Ability Time and work

If 5 engines consume 6 metric tonnes of coal when each is running 9 hours a day. How much coal (in metric tonnes) will be needed for 8 engines, each running 10 hours a day, it being given that 3 engines of the former type consume as much as 4 engines of latter type?

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Explanation:

Coal consumed by one engine of type 1
=6/(5*9)
=2/15 metric tonnes per hour
3 engines of type 1 consume as much as 4 engines of type 2
Therefore,
Coal consumed by one engine of type 2=(3/4)*(2/15)
=1/10 MT/hour
Coal consumed by 8 engines (of type 2),running 10 hours a day
=(1/10)*8*10
=8 metric tonnes.