A father is twice as old as his son 20 years ago the age of the father was 12 times the age of the s...........

Quantitative Aptitude Problems based on Ages

A father is twice as old as his son. 20 years ago, the age of the father was 12 times the age of the son. The present age of the father (in years) is

Let sons age = x. Then, fathers age = 2x.
12(x—2O) = (2x - 20) so x = 22
Fathers present age = 44 years

Hence, option 4 is the correct answer.

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