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A train covered a certain distance at a uniform speed. If the train had been 6 km/h faster, then it would have taken 4 hours less than the scheduled time. And, if the train were slower by 6 km/h, then the train would have taken 6 hours more than the scheduled time. The length of the journey is
700 km
740 km
720 km
760 km
Let the length of the journey be d km and the speed of train be SS km/hr.
Then,
dS+6=t−4dS+6=t−4-----(i)
dS−6=t+6dS−6=t+6------(ii)
Subtracting the 1 equation from another we get:
dS−6−dS+6=10dS−6−dS+6=10------(iii)
Now t=dst=ds
Substitute in equation (i) and solve for dd and SS
We get S=30S=30 and dd = 720 km
Hence, option 3 is the correct answer.
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