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Study the following table carefully and answer the questions that follow: The table shows the number of students (boys and girls) who participated in different activities from 5 schools – A, B, C, D and E and the individual percentages. (Though some values are missing)
Students from school A who did not take part in Swimming and Dancing is 147. The number of students who took part in Swimming is 49 more than who took part in Dancing. Find the number of students who took part in swimming from same school.
187
196
173
205
30% of z = 147 [z – number of students in school A] Solve, z = 490 Let students who took part in swimming is x% and dancing is y% So x + y = 70% (100-30) ………………………(1) Also x% of 490 = 49 + y% of 490 ………….(2) Solve both equations, x = 40% So students from school A who took part in Swimming = 40% of 490 = 196
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