Explanation:

Let’s break this down step by step:

- Seven people, sitting on a heptagon, all facing the center.

- A is placed anywhere. F is immediately to A’s right. So we have: A - F.

- D is second to the right of A. Since everyone faces the center, let’s count: immediate right = F, then next right = D. So it’s A - F - X - D (moving right).

- C is second to the left of A. The immediate left of A is one seat, then next is C.

- G is sitting next to C. We don’t know if it's left or right, but they must be together.

- B is second to the right of F. F’s immediate right is X (already penciled in from earlier), so the seat after X is B.

Let’s slot what we know so far:

A - F - X - D (right side), and B is two to the right of F (so, after X and D, so F - X - D - B).

On the left: A’s immediate left is X, the next is C (so, X - C - A). G is next to C.

Now, filling in:

1. Let's assume - moving clockwise: C - X - A - F - X - D - B

2. G can be next to C. Place G on the seat next to C.

3. Only one seat remains empty, and that will be E.

Review the options for E:

- Immediate left of F? Not possible.

- Immediate right of C? C, G, E. Yes, E can be there—so this fits!

- Immediate right of A? No.

- Immediate left of B? No.

So, the answer is:

Option: 2, Immediate right of C

Here’s what this really means: by piecing together each clue, only the seat immediately to the right of C fits for E. Simple logic, just a bit of careful seat-placing, and it lines up.