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Two numbers differ by 10. If their LCM is 120 and HCF is 10, then the sum of the numbers is:
130
120
70
50
- LCM (Least Common Multiple) and HCF (Highest Common Factor) are defined for two numbers. Here, LCM = 120 and HCF = 10.
- Let the numbers be \( x \) and \( y \) such that \( x > y \).
- Given \( x - y = 10 \).
- From the relationship between LCM, HCF, and the product of numbers, \( x \times y = \text{LCM} \times \text{HCF} = 120 \times 10 = 1200 \).
- Using \( x = y + 10 \), substitute in the equation:
$$ (y + 10) \times y = 1200 $$
$$ y^2 + 10y = 1200 $$
$$ y^2 + 10y - 1200 = 0 $$
- Solve the quadratic equation to find \( y \). The solution leads to \( y = 30 \) and \( x = 40 \).
- So, the sum of the numbers is \( x + y = 40 + 30 = 70 \).
- Options:
1. 130: Incorrect, doesn't satisfy the conditions.
2. 120: Incorrect, doesn't satisfy the conditions.
3. 70: The correct sum, both the numbers satisfy the conditions.
4. 50: Incorrect, doesn't satisfy the conditions.
By: santosh ProfileResourcesReport error
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