The population of a village decreases eve1y year at the rate of 3 If the present population is 28227...........

Quantitative Aptitude (MTS) Percentage

The population of a village decreases eve1y year at the rate of 3%. If the present population is 28227, what was the population

of the village two years ago?

This questions was previously asked in

SSC MTS 8th July 2022 Shift-1

31868

30000

32472

30560

- The current population is 28,227, decreasing at a rate of 3% annually.

- We need to find the population two years ago.

- Using the formula for population decrease:

\text{Previous Population} = \frac{\text{Current Population}}{(1 - \text{Rate})^n}

where \(\text{Rate} = 0.03\) and \(n = 2\).

- Calculate:

\text{Previous Population} = \frac{28227}{(1 - 0.03)^2} = \frac{28227}{0.9409} \approx 30,000

- Option 2: 30,000 seems correct based on this calculation.

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