An engineering student has to secure 25 marks to pass He gets 56 and fails by 34 marks Find the maxi...........

Quantitative Aptitude (CSC) Percentage

An engineering student has to secure 25% marks to pass. He gets 56 and fails by 34 marks. Find the maximum marks.

385 marks

360 marks

410 marks

435 marks

- To pass, the requirement is securing 25% of total marks.

- The student scored 56 marks and failed by 34 marks.

- So, he needed 56 + 34 = 90 marks to pass.

- 25% of total marks must equal 90 marks.

- If 25% equals 90 marks, then total marks = \( \frac{90 \times 100}{25} \) = 360 marks.

- Therefore:

- Option 1: 385 marks - Not correct, since 25% of 385 is not 90.

- Option 2: 360 marks - Correct, as calculated, 25% of 360 is 90.

- Option 3: 410 marks - Not correct, since 25% of 410 is not 90.

- Option 4: 435 marks - Not correct, since 25% of 435 is not 90.

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