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Four persons A,B,C and D are hired to do work. A, C and D can complete the task in 16 days while working together. Find the number of days taken by B alone to complete the task.
Statement I: C and D can complete the task in 24 days, B is 100% more efficient than A.
Statement II: A alone can complete the work in 48 days and ratio of efficiency of C and D is 1:2 resp.
Both are necessary
From I: Let the total work lcm(16,24) = 48 units Work done by A,C and D in one day = 48/16 = 3 units Work done by C and D in one day = 48/24 = 2 units Work done by A in one day = 3-2 = 1 unit Therefore, number of days taken by A to complete the work = 48/1 = 48 days The time taken by B to complete the work = 48/2 = 24 days This statement is alone sufficient. From II: Let the efficiency of C and D be x and 2x resp. 1/48 + x + 2x = 1/16 =>x = 1/72 This statement is not sufficient to answer.
Hence, option 2 is the correct answer.
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